Solve Torque & Tension | Get Help Now!

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    Tension Torque
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To solve for tension in the wire, start by drawing a free body diagram to identify all forces acting on the pole, including tension and reactions. The pole is in equilibrium, meaning the sum of forces in any direction equals zero. The tension in the wire can be calculated using the known weight of the pole, which is 5 kg. The calculated tension is confirmed to be 276.64 N. This approach will help clarify the forces acting on the pole rather than the wall.
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http://s87050427.onlinehome.us/scan.jpg
how would I do this, and how would I solve for tension in the wire?
What i did was completely wrong, and I appologize in advance for my horrible horrible, handwriting.
Thanks in advance!
oh, and a quick response would be greatly appreciated, my exam is tomorrow :)
 
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:smile: lol... I can't seem to make that picture the right size, it's either really really big, or really really tiny..

can you post the question? also post the work you've done so far
 
nevermind,,, I think I can make it out
 
Sorry,, the computer lab is closing,,, I didn't have time to work on your question
 
First draw a freebody diagram. You should be able to identify all the forces even though some of them would be eliminated from the mathematical analysis. This includes reactions, tension, etc.
 
how exactly would i model the forces acting on the wall?
the hypotnuse is not 90degrees, so I am not sure how i would handle that
 
slipF said:
how exactly would i model the forces acting on the wall?
the hypotnuse is not 90degrees, so I am not sure how i would handle that
You want the forces acting on the pole, not on the wall. The forces that the wall exerts on the pole are given.

Big hint: Since the pole is in equilibrium, the sum of the forces acting on it (in any direction) is zero.
 
Last edited:
ah ok, so the pole is 5kg
is it correct in saying the tension in the wire is 276.64 N too?
 
You got it.
 

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