Solve Trig Question: tan(2θ) = cot(φ)

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The equation tan(2θ) = cot(φ) can be simplified by recognizing that cot(φ) is equivalent to 1/tan(φ). This leads to the relationship 2θ = atan(1/tan(φ)), but further simplification can be challenging. An alternative approach is to use the identity that cot(φ) equals the tangent of the complement, leading to the conclusion that 2θ = π/2 - φ. Additionally, the equation can be expressed as 2tan(θ)/(1 - tan²(θ)) = 1/tan(φ) for further analysis. Ultimately, understanding the relationship between tangent and cotangent is key to solving for θ.
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[SOLVED] Trig Question

Homework Statement


Let's say I have tan(2\theta) = cot(\phi) I'm not quite sure how to simplify it (I want to solve for theta) I could say tan(2\theta) = 1 / tan(\phi)
2\theta = atan( 1 / tan(\phi) ) but then I'm not sure what to do after that.
Do I take the atan of 1 and tan(\phi)?

I know another method to find it is to say cot(\phi) = \pi/2 - tan(\phi) but I don't understand that either because 2\theta = atan( \pi/2 - tan\phi ) != \pi/2 -\phi (not exactly at least)
The answer as far as I know is supposed to be 2\theta = \pi/2 -\phi
 
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Remember that that the tangent of angle is the cotangent of its complement and go from that definition.

OR you could say that


tan(2\theta) = cot(\phi) \Rightarrow \frac{2tan\theta}{1-tan^2\theta}=\frac{1}{tan\phi}

and solve from there.

Two ways really, one is easier than the other though.
 
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