Solve x^2 + (-1/2x + 5)^2 = 25

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To solve the equation x^2 + (-1/2x + 5)^2 = 25, first expand the squared term to obtain x^2 + (-x/2 + 5)^2 = 25. This simplifies to x^2 + (x^2/4 - 5x + 25) = 25. Further simplification leads to the equation 5x^2/4 - 5x = 0, which can be factored to x(x - 4) = 0. The solutions to the equation are x = 0 or x = 4.
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How do we solve this equation:


x^2 + (-1/2x + 5)^2 = 25

Thanks in advance
 
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Expand that squared term and you'll see that this quadratic equation simplifies nicely.
 
That's assuming that you mean ((-1/2)x + 5)^2 and not (-1/(2x)+ 5)^2.
 
Thanks, then

x^2 + (-x/2 + 5)^2 = 25

x2 + x2/4 - 5x + 25 = 25

5x2/4 - 5x = 0 (* 4/5)

x2 - 4x = 0

x(x - 4) = 0

x = 0 or x = 4.
 

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