Solve y = -1/4x - 12 Perpendicular Through (3, -4)

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To find the equation of a line perpendicular to y = -1/4x - 12 that passes through the point (3, -4), the slope of the new line must be the negative reciprocal of -1/4, which is 4. Using the point-slope form of a line, y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point (3, -4), the equation can be derived. The calculation involves substituting the point into the equation to solve for the y-intercept, b. Ultimately, the resulting equation will represent the desired perpendicular line. Understanding the relationship between the slopes of perpendicular lines is key to solving this problem.
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Perpendicular to y = -1/4x - 12 passing through (3, -4).
 
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Hint: If two lines are perpendicular, what does this tell you about their slopes?
 
They intersect?
 
well, the lines intersect, yes. but you know what the slope of the first line is, right? your equation is in y =mx+b format so you can tell just by looking.

the slope of the second line will be the opposite reciprocal of the first slope.
 
opposite reciprocal?

:P

I prefer to use the term negative reciprocal.
 
I grew fond of "opposite" because there's no confusion if you are talking about the slope of a line that's perp to a line with a negative slope. but that's just me!
 
anyhoo, power animals, what we're saying is that if a line has a slope of positive 3, for example, then the slope of a line that is perpendicular to it would be -1/3.
 
so if the slope of a line is -1/4, then the slope of a line that is perpendicular to it would be...?
 
or when you multiply both slopes together you get -1 ?

my maths teacher had a strange way of explaining things...
 
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yes. when multiplied together they will equal -1

so you can see it by setting -1=m1*m2 where m1 or m2 to -1/4.

do you need help finding the whole equation based on that slope and point? you can just plug an x and a y into the y=mx+b way and solve for b too.
 
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