Solved: Calculate Ion Concentration (27.6 g)

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The discussion focuses on calculating ion concentration from a given mass of MgBr2. The correct dissociation of MgBr2 into its ions is highlighted, emphasizing that it produces one magnesium ion and two bromide ions. A key error noted is that the moles of MgBr2 should be halved due to the two bromide ions formed, affecting the overall concentration calculation. Clarification is provided regarding the notation of bromide ions versus diatomic bromine. The conversation concludes with appreciation for the assistance in correcting the calculations.
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[SOLVED] Ion concentration

Homework Statement


http://img225.imageshack.us/img225/9918/chemch0.jpg​


Homework Equations


C = n/v


The Attempt at a Solution


My work is shown up above. Sorry if my work looks a little messy. My answer is 27.6 grams.
 
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I just want someone to tell me if I'am right, and correct me if I'am not.
 
good effort

your error is in your dissociation equation

MgBr2 --> Mg+2(aq) + 2Br-(aq)

the bromide ion is twice the concentration of the MgBr2 so the moles of MgBr2 is half what you calculated (.15/2).

your mass of MgBr2 is half of your answer
 
But isn't Br supposed to have a subscript of 2?
 
MgBr2 is a compound that dissociates into its ions in water.

the Br- ions don't stay together in water so you get 2 Br- ions

Br2 by itself is only written when you are referring to bromine as an diatomic element, not as ions in solution
 
Thanks a lot for the help. :approve:
 
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