Solved: Inverse Laplace Transform of $\frac{e^{-2s}}{s^2+s-2}$

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Homework Help Overview

The discussion revolves around finding the inverse Laplace transform of the expression \(\frac{e^{-2s}}{s^2+s-2}\). The problem involves concepts from Laplace transforms, particularly focusing on time shifting and partial fraction decomposition.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using partial fractions to decompose the given expression and express concerns about applying the time shift property correctly. There are inquiries about modifying terms to align with known inverse transforms.

Discussion Status

Some participants have offered guidance on how to approach the problem, including steps for handling the exponential term and separating the components for inverse transformation. There is an acknowledgment of confusion regarding the application of the time shift property, but productive suggestions have been made to clarify the process.

Contextual Notes

One participant notes a lack of experience with complex analysis, which may limit their approach to the problem. There is also mention of difficulties in editing previous posts, which may affect the clarity of the discussion.

jesuslovesu
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[SOLVED] Laplace transform

Homework Statement



Find the inverse laplace transform of \frac{e^{-2s} }{s^2 + s - 2}

Homework Equations





The Attempt at a Solution



I'm able to do about half of the problem
using partial fractions, I've found
\frac{e^{-2s}}{3(s+1)}+\frac{e^{-2s}}{3(s-2)}

I can find the inverse Laplace transform of the latter part of that expression 1/3u_2(t) e^{t-2} unfortunately, I don't know how I can modify the first part so that it's shifted by -2. Anyone know what I should do?
 
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Use calculus of residues (have you taken complex analysis yet?)
 
jesuslovesu said:
1. The problem statement, all variables and given/known Anyone know what I should do?

Look in the wiki page about laplace transformations under 'time shifting'.
 
Unfortunately I haven't studied complex analysis.
I made an error in my original post (and I can't edit it for some reason)
It's now worse than before
s^2 + s - 2 = (s+2)(s-1)
-\frac{e^{-2s}}{3(s+2)} + \frac{e^{-2s}}{3(s-1)}

I see the time shift equation on wikipedia, but since the 's' is in the denominator I don't see how to shift either so that they match up with u_2(t)
 
jesuslovesu said:
I see the time shift equation on wikipedia, but since the 's' is in the denominator I don't see how to shift either so that they match up with u_2(t)

Hum, you seem to be misreading it, do this for your two terms separately

Step 1-- cover the exponential up with your hand. What's left is your 1/(s+2) (or 1/(s-1) for the other term) with your 3 and your signs of course. Call that F(s).

Step 2-- look up on a table the f(t) such that L[f]=F(s) from Step 1. Write that f(t) down.

Step 3-- now look on that exponential you were ignoring before (exp(-2s)) that's telling you that your answer will not be f(t), but instead be f(t-2)H(t-2) where H is the unit step function. So write that down.

Now repeat for the other term and then add the two expressions you get from Step 3 together.
 
got it now thanks, those steps are really handy
 

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