- #1

phsyics_197

- 11

- 0

## Homework Statement

Question as in image:

## Homework Equations

## The Attempt at a Solution

When I did Mesh, I got this:

-20j-20Ia+(Ia-Ib)2j=0

(Ib-Ia)2j-(Ib-5)j-(Ib-Ic)50=0

-(Ic-Ib)50-(Ic-5)8j-2(Ia-Ib)=0

2(Ia-Ib)-100Id=0

Ia-Ib=Ix

**This is done from Left to Right**

One thing I am not sure about is the Sin voltage source. I believe you convert it to Cos first? Then it should give you -20j.

Well, when I solved the above equations in Matlab, I got Ix = -6.4622 - 0.5310i.

I was wondering if that is correct, and how could I verify it?

Thanks