Solving a Complex Homework Problem: Tip or Slide?

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SUMMARY

The discussion focuses on calculating the force required to tip a storage bin weighing 7100 N, with dimensions of 2.2 m width, 3 m height, and 1.6 m depth, at an angle of 20 degrees. The coefficient of friction between the bin and the floor is 0.43, which affects whether the bin will tip or slide. Key equations used include torque (T=R∗F∗sin(θ)) and the sum of torques (ΣT = 0). The calculated radius (R) for tipping is 2.4 m, leading to a required force of 7600 N to initiate tipping.

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Homework Statement



I have been trying this question since 5 hours but I am lost ! Any help would be appreciated

Some moron kids are trying to tip over a storage bin as shown. The bin weighs 7100 N, w = 2.2 m, h = 3 m, d = 1.6 m, and theta = 20 degrees. With what force do they need to push in order to tip the bin over?
F= ? Newtons
If the coefficient of friction between the box and the floor is 0.43, calculate the force of friction on the box and determine whether it will slide or tip over
Tip or Slide?

Homework Equations


-T=R∗F∗sin(θ)
ΣT = 0

The Attempt at a Solution


R=sqrt(1.8^2+1.6^2)=2.4m
F=??
R=sqrt(0.9^2+1.5^2)=1.75m
F=7600N
now what??
 

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When you do these problems it is helpful to describe what you are doing in words - if nothing else, it focusses you mind on the physics.

What sort of motion does the box have to undergo to get tipped? Where is the pivot?
Where does the main force opposing the tipping act? In which direction?
After that it is a matter of torques and reason - though you could try doing it in terms of conservation of energy.
 

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