Solving a Differential Equation

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SUMMARY

The discussion centers on solving the first-order linear differential equation \(P^{'}(t)+(\lambda +\mu )P(t)=\lambda\). The user attempted to solve it by multiplying both sides by \(e^{(\lambda +\mu )t}\) and integrating, but incorrectly simplified the solution to \(P(t)=\frac{\lambda}{\lambda + \mu}\). The correct solution involves incorporating the constant \(C\) and is given by \(P(t)=\frac{\lambda}{\lambda + \mu}(1 - e^{-(\lambda + \mu)t})+P(0)e^{-(\lambda + \mu)t}\). The user was advised to ensure the constant \(C\) is multiplied correctly during the integration process.

PREREQUISITES
  • Understanding of first-order linear differential equations
  • Familiarity with integration techniques
  • Knowledge of the exponential function and its properties
  • Basic concepts of initial conditions in differential equations
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  • Learn about initial value problems and how to apply them
  • Explore the concept of homogeneous and particular solutions
  • Practice solving differential equations using different techniques, such as separation of variables
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Students studying differential equations, educators teaching calculus, and anyone looking to strengthen their understanding of first-order linear differential equations.

Obraz35
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Homework Statement


<br /> \[P^{&#039;}(t)+(\lambda +\mu )P(t)=\lambda \]<br /> <br />

I have never worked with differential equations before and I am trying to work off of the one example we did in class, but I can't figure out where I am going wrong.

Homework Equations





The Attempt at a Solution


The first thing I did was multiply both sides by
<br /> \[e^{(\lambda +\mu )t}\]<br />

Then,
<br /> \[\frac{d}{dt}[e^{(\lambda + \mu)t}P(t)]=\lambda e^{(\lambda + \mu)t}\]<br />

Integrating both sides,
<br /> \[e^{(\lambda + \mu)t}P(t)=\frac{\lambda e^{(\lambda + \mu)t}}{\lambda + \mu} + C\]<br />

which seems to give me
<br /> \[P(t)=\frac{\lambda}{\lambda + \mu}\]<br />

but I know that this is not correct since I am supposed to showing that the solution is
<br /> \[P(t)=\frac{\lambda}{\lambda + \mu}(1 - e^{-(\lambda + \mu)t})+P(0)e^{-(\lambda + \mu)t}\]<br />.

I don't think I am solving for C correctly but since I have never really been taught this I'm not quite sure what to do or how to get that solution. I'd really appreciate it if someone could let me know where I am going wrong.
 
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Obraz35 said:

Homework Statement


<br /> \[P^{&#039;}(t)+(\lambda +\mu )P(t)=\lambda \]<br /> <br />

I have never worked with differential equations before and I am trying to work off of the one example we did in class, but I can't figure out where I am going wrong.

Homework Equations





The Attempt at a Solution


The first thing I did was multiply both sides by
<br /> \[e^{(\lambda +\mu )t}\]<br />

Then,
<br /> \[\frac{d}{dt}[e^{(\lambda + \mu)t}P(t)]=\lambda e^{(\lambda + \mu)t}\]<br />

Integrating both sides,
<br /> \[e^{(\lambda + \mu)t}P(t)=\frac{\lambda e^{(\lambda + \mu)t}}{\lambda + \mu} + C\]<br />
You were doing great up to here (above). You multiplied both sides of the equation by
<br /> e^{-(\lambda + \mu)t}<br />
but forgot to multiply the constant C.
Obraz35 said:
which seems to give me
<br /> \[P(t)=\frac{\lambda}{\lambda + \mu}\]<br />

but I know that this is not correct since I am supposed to showing that the solution is
<br /> \[P(t)=\frac{\lambda}{\lambda + \mu}(1 - e^{-(\lambda + \mu)t})+P(0)e^{-(\lambda + \mu)t}\]<br />.

I don't think I am solving for C correctly but since I have never really been taught this I'm not quite sure what to do or how to get that solution. I'd really appreciate it if someone could let me know where I am going wrong.
 

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