Solving a Difficult Integral: Strategies and Advice

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SUMMARY

The integral \int \frac{x}{\sqrt{x^4 + 10 x^2 - 96 x - 71}}\ \mbox{d}x presents significant challenges in finding an elementary solution. Forum participants discussed various strategies, including completing the square and trigonometric substitution, but concluded that the integral cannot be expressed in elementary terms. A suggestion was made to rewrite the denominator as [{(x^2+5)^2/96 - 1}^2 + 5]^2, which may simplify the problem. Ultimately, the integral's complexity necessitates advanced techniques beyond basic calculus.

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Homework Statement



<br /> \int \frac{x}{\sqrt{x^4 + 10 x^2 - 96 x - 71}}\ \mbox{d}x<br />

The Attempt at a Solution


I don't see what's useful completing a square, gonio substitution (or even a useful substitution). Does anyone have an idea?
 
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The denominator can be replaced as [{(x^2+5)^2/96 - 1}^2 + 5]^2.

P.S. That /96 is to the whole (x^2+5)^2 expression.
 
MadHawk said:
The denominator can be replaced as [{(x^2+5)^2/96 - 1}^2 + 5]^2.

P.S. That /96 is to the whole (x^2+5)^2 expression.
That's a degree 16 polynomial, there MadHawk.

dirk_mec1 said:

Homework Statement



<br /> \int \frac{x}{\sqrt{x^4 + 10 x^2 - 96 x - 71}}\ \mbox{d}x<br />


The Attempt at a Solution


I don't see what's useful completing a square, gonio substitution (or even a useful substitution). Does anyone have an idea?

Was this a homework problem, Dirk? Could you provide some context as to where it arose. According to the integrator at http://integrals.wolfram.com/index.jsp?expr=x/Sqrt[x^4+10*x^2-96*x-71]&random=false, it would seem the integral as you have written it cannot be expressed in elementary terms.
 
MadHawk said:
The denominator can be replaced as [{(x^2+5)^2/96 - 1}^2 + 5]^2.

P.S. That /96 is to the whole (x^2+5)^2 expression.

Your expression isn't even of the same degree as the denominator in the original expression:eek:

I think you'd better double check your math on that one!:wink:
 
dirk_mec1 said:

Homework Statement



<br /> \int \frac{x}{\sqrt{x^4 + 10 x^2 - 96 x - 71}}\ \mbox{d}x<br />


The Attempt at a Solution


I don't see what's useful completing a square, gonio substitution (or even a useful substitution). Does anyone have an idea?

Hmmm... are you sure that -96x is supposed to be there?
 
Well, it was just pure innocent fun. The actual quantity under root is (x^2+5)^2 - 96(x+1). From here, I think, it can be done. Sorry folks, for the joke above.
 
gabbagabbahey said:
Hmmm... are you sure that -96x is supposed to be there?

Yes, this IS the correct integral. Furthermore there is an exact solution which can be written in elementary functions. What can you advice me to do? Is Madhawks suggestion the way to tackle this integral?

Where are Dick and HallsofIvy? Or did I scare them away :wink:
 
Last edited:

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