Solving a Frictional Problem with No Given Masses

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The discussion focuses on solving a frictional problem involving a crate in a pickup truck without given masses. The key question is how to determine the coefficient of static friction when only acceleration and distance are provided. A force diagram is essential, revealing that masses cancel out and the coefficient of friction is related to the acceleration due to gravity. The calculation process shows that using a hypothetical mass allows for the determination of the coefficient, which is dimensionless. Understanding the relationship between normal force and gravitational force is crucial, as they may not always be equal in different scenarios.
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In this section, I am trying to determine frictional forces between surfaces and masses. However, in this type of problem, no masses are given. Here is a type of question:

A crate is carried in a pickup truck traveling horizontally at 15.0 m/s. The truck applies the brakes for a distance of 28.7 m while stopping with uniform acceleration. What is the coefficient of static friction between the crate and the truck bed if the crate does not slide?

I have determined the truck brakes at -3.92 m/s^2. The formula I have for coefficient of static friction is Frictional Force = Coeff. of Friction * Normal Force. However, no forces or masses are given. How can I solve this type of problem?

Thank you
 
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You need to draw your force diagram. You will find that the masses cancel and that the acceleration from friction will be some percentage of acceleration of gravity, and that will be your coefficient.
 
I tried to set the mass of the crate to 100kg. After drawing a force diagram, I'm not sure I am doing it right. Force Normal and the Force of Gravity should equal one another. If Net Force = Mass * Acceleration, and the mass is 100kg*-3.92 m/s, you get a negative net force of -392 N. 392 N/981N(Normal Force) = .400N. Is this the coefficient of friction?
 
Almost ... the Units cancel (392 N / 981 N) = 0.40 , unitless.
The co-efficient of friction is an efficiency , so it is dimensionless.

By the way, Normal Force = gravity Force here, but it often isn't ... watch out!
 
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