Solving a Nonlinear ODE for Parachute Area in Free Fall

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SUMMARY

The discussion focuses on solving a nonlinear ordinary differential equation (ODE) related to parachute dynamics during free fall. The equation presented is m (dV/dt) = mg - (1/2)(air density)(drag constant)(area parachute)(V)^2, which simplifies to dV/dt = g - (k/m)V^2, where k represents the constants involved. The key step involves using partial fractions to integrate the equation, allowing for the determination of the parachute area based on various parameters such as mass, drag, and air density.

PREREQUISITES
  • Understanding of nonlinear ordinary differential equations (ODEs)
  • Familiarity with concepts of drag, gravity, and air density
  • Knowledge of integration techniques, specifically partial fractions
  • Basic physics principles related to free fall and parachute dynamics
NEXT STEPS
  • Study the method of integrating nonlinear ODEs using partial fractions
  • Explore the effects of varying drag constants on parachute performance
  • Learn about the physical principles of free fall and terminal velocity
  • Investigate numerical methods for solving ODEs when analytical solutions are complex
USEFUL FOR

Students in physics or engineering courses, particularly those studying dynamics and fluid mechanics, as well as anyone interested in the mathematical modeling of parachute systems.

francisg3
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Homework Statement


We recently discussed a problem in class involving free fall and parachutes.One of the examples was to solve for the area of a parachute in drag,gravity,air density,mass and the speed at which the object deployed the parachute and the speed it hit the ground out. I'm pretty sure I know how to do the porlbem if I could only get past the first few steps. My guess is that I need to solve the following nonlinear ode:

m (dV/dt) = mg-(1/2)(air density)(drag constant)(area parachute)(V)^2
i replaced the equation with something like this to simplify it:
m (dV/dt) = mg-kV^2 where k is all those constants

now I'm familiar with seperable ode's and this is the form i obtained:
dV/dt = g-(k/m)V^2

from then on i am lost, i think i just need a bit of help onto the next step or two then i should be able to get the problem rolling. Any help or input would be greatly appreciated! Thank you.
 
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Hi francisg3! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)
francisg3 said:
dV/dt = g-(k/m)V^2

yes, so dV/(g-(k/m)V2) = dt :wink:
 
And you can use partial fractions to integrate that.
 

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