Solving a Problem I'm Hopeless With: A Hint Needed!

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Homework Statement


[PLAIN]http://img517.imageshack.us/img517/2516/62548919.jpg


I'm hopeless to solve this problem
you can give me a hint before solving the problem!
Thanks in advance
 
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You might try rewriting this as
[tex]\lim_{n \to \infty}\frac{(A + (1/n))^4 - A^4}{1/n}[/tex]

In this form, the expression has the indeterminate form [0/0], so you can use L'Hopital's Rule on it.
 
still can't solve it ...we can factorize the numerator but still makin no sense...Can u make it simpler?
 
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Did you try L'Hopital's rule?

Can you post your work?
 
Do you know how to use L'Hopital's Rule?

A slightly different approach is this, with h = 1/n
[tex]\lim_{h \to 0^+}\frac{(A + h)^4 - A^4}{h}[/tex]
 
No...I don't know anything about this rule we don't study it at school and they can't give us a problem on a rule which we haven't studied yet :(
 
Well, if you use Mark44's substitution you won't need to use L'Hopital's rule
 
You need to show us what work you have done on the problem, Misr, even if it's just thoughts about it. It is unacceptable to just post a question and say "I can't do it".

And a reminder for homework helpers: our goal is to help posters do a problem, not to give them answers. The OP has gotten plenty of advice, and his own idea that he didn't post the work for sounds like a very workable approach too. If he doesn't start showing that he's done anything with any of that, then it is inappropriate to give further "help".
 
You need to show us what work you have done on the problem, Misr, even if it's just thoughts about it. It is unacceptable to just post a question and say "I can't do it".
[/quoye]
Yep, I totally agree and I DO respect this ...but my work is very random and terrible and it has nothin to do with the right answer...I tried your creative ways before..so I agree with that ...it gives excellent results
hope you can understand this
Thanks very much
 
Have you tried expanding:
[tex] (A+n^{-1})^{4}=A^{4}+4\frac{A^{3}}{n}+6\frac{A^{2}}{n^{2}}+4\frac{A}{n^{3}}+\frac{1}{n^4}[/tex]
I think that this will solve your problem.