Solving a Reduction of Order ODE with Initial Conditions | Math Homework Help

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SUMMARY

The discussion focuses on solving the second-order ordinary differential equation (ODE) given by y'' - y' e^{y'^2 - y^2} = 0 with initial conditions y(0) = 1 and y'(0) = 0. Participants explore the substitution y' = p, leading to the challenge of integrating e^{y^2}, which is deemed unintegratable. The consensus suggests that the solution is y = 1, and there is a call for a proof to confirm this as the only solution under the specified conditions.

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Homework Statement



Solve:
[tex] y'' -y' e^{y'^2-y^2} = 0[/tex]

y(0) = 1
y'(0) = 0

Homework Equations





The Attempt at a Solution



No idea how to use it.
If I use the substituion y' = p, and y'' = p'p I need to integrate [itex]e^{y^2}[/itex] which is unintegratable. What should I do?
 
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According to your DE and initial conditions, what is [itex]y''(0)[/itex]? How about [tex]\left.\frac{d^n y}{dx^n}\right|_{x=0}[/tex] ? What might you expect the solution to be if all the derivatives are zero at some point? Can you prove that is the only solution?
 
I get what you're trying to say - that the solution is y=1.
I don't know how to prove it though.
 

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