Solving a Rocket Motion Problem

AI Thread Summary
A rocket is launched with an acceleration of 22.8 m/s at an angle of 62.4 degrees for 8.95 seconds before becoming a projectile. The discussion includes calculations for both straight-line and projectile motion, with key values for initial and final velocities, distances, accelerations, and time. The provided answers for the straight-line motion are confirmed as correct, including the use of the Pythagorean theorem and the formula vf = vi + at. It is clarified that the time remains consistent across all motion phases, as the rocket travels straight until fuel depletion. The conversation concludes with validation of the calculations and understanding of motion dynamics.
drew1989
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Ok here's a question i had for homework, but i am having some trouble with it:

a rocket is fired from rest with an acceleration at=22.8m/s at an elevation angle of theta=62.4. the rocket travels in a straightline for 8.95 seconds, when the fuel runs out. at this time it becomes a projectile and falls back to the ground. fill in the tables

they ask for:

straightline

total horizontal verticle

vi vi vi
vf vf vf
d d d
a a a
t t t

and they ask for

projectile

up down horizontal


my answers were

total horizontal verticle

vi 0 vi 0 vi 0
v 204.06 vf 159.18 vf 147.18
d 913.17 d 809.25 d 423.07
a 22.8 a 20.2 a 10.6
t 8.95 t 7.9 t 4.2

i got these answers by using the pythagorean theorem and using the vf=vi+at formula. if these are right could you tell me, if not tell me what i was doing wrong. after i get to projectile it is easy but i think i made a mistake. would the time be the same for all?
 
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projectileup down horizontalvi 204.06 vi 147.18 vi 159.18vf 0 vf 0 vf 0d 423.07 d 913.17 d 809.25a -10.6 a -20.2 a 0t 4.2 t 7.9 t 7.9Yes, your answers for both tables are correct. The time for each motion would be the same because the rocket travels in a straight line for 8.95 seconds until it runs out of fuel and becomes a projectile.
 
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