Solving a Spirit-in-Glass Thermometer Problem

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The discussion revolves around solving problems related to a spirit-in-glass thermometer, specifically calculating the mass of spheres at different temperatures and the forces acting on them. The first sphere, with a radius of 1.400 cm, has a mass of 9.07 grams at 20.0°C, while the second sphere must weigh 8.98 grams to remain in equilibrium at 30.0°C. The participant initially struggled with determining the upward force exerted on the first sphere when it sank to the bottom of the tube. After clarification, they realized their error in unit conversion from grams to Newtons for the final force calculation. The discussion highlights the importance of proper unit management in physics problems.
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Homework Statement


The "spirit-in-glass thermometer", invented in Florence, Italy, around 1654, consists of a tube of liquid (the spirit) containing a number of submerged glass spheres with slightly different masses (see the figure below). At sufficiently low temperatures all the spheres float, but as the temperature rises, the spheres sink one after the other. The device is a crude but interesting tool for measuring temperature. Suppose that the tube is filled with ethyl alcohol, whose density is 0.78945 g/cm3 at 20.0° and decreases to 0.78097 g/cm3 at 30.0°C.

If one of the spheres has a radius of 1.400 cm and is in equilibrium halfway up the tube at 20.0°C, determine its mass?

When the temperature increases to 30.0°C, what mass must a second sphere of the same radius have in order to be in equilibrium at the halfway point?

At 30.0°C the first sphere has fallen to the bottom of the tube. What upward force does the bottom of the tube exert on this sphere

Homework Equations


buoyant force = mg

The Attempt at a Solution


So I go the first 2 correct.

For the first one I had: M_sphere*g = p_alcohol_at_20 * g * 4/3 pi r^3
solving for M_sphere, I got 9.07 grams

For the second one I had M_sphere2*g = p_alcohol_at_30 * g * 4/3 pi r^3
solving for M_sphere2, I got 8.98 grams

For the last part, I set up this equation:
buoyant force + normal force = mg_sphere
p_alcohol_at_30*V_sphere*g + N = M_sphere*g
But this equation has 2 unknowns, N (the normal force) and p_sphere, the spheres density. I'm not even a 100% sure if 1.4cm is the radius of this sphere so I may not even know the volume meaning 3 unknowns... What am I missing?
Thanks in advance
 
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With 'first sphere', they mean the one for which you calculated the mass of 9.07 grams. You also have the volume for it.
 
No reason to expect that. And no need:
Just write a force balance for the sphere on the bottom.
 
Ok. I was referring to the problem where it sat halfway up in the liquid.
Abid did set a force equation up for the last problem though.
 
Ok guys after some experimentation I found what was wrong. When I found the force, I found my units had grams, and the answer wanted Newtons which has kilograms... :rolleyes: So I set up the force equation and then divided the result by 1000 and the answer worked. Thank you guys!
 
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