Solving a Third Order Differential Equation with Initial Conditions

  • Thread starter Thread starter math_addict
  • Start date Start date
math_addict
Messages
5
Reaction score
0
I'm interested in solving this 3rd order DE y'''=3*y*y' with conds y(0)=-2, y'(0)=0, y''(0)=4,5. Thanks for any ideas.. I've the right solution, but the problem is how to achieve it.
 
Physics news on Phys.org
try
\frac{3}{2}\frac{d}{dt}(y^2)=3y\dot{y}
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top