Find the value of x between 0 degrees and 360 degree satisfying the equation(adsbygoogle = window.adsbygoogle || []).push({});

10sin^2x+ 10sin x cos x - cos^2x = 2 this is how i have attempted.........................

10 sin^x+ 10sin2x/2 - cos^x = 2

I used the property sin 2x = 2 sin x cos x and substituted sin x cos x with sin 2x/2 giving me.................

11sin^2x + 5sin 2x -3 =0 on reaching here i got stuck....kindly advise

**Physics Forums - The Fusion of Science and Community**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Solving a trigonometric equation

Loading...

Similar Threads - Solving trigonometric equation | Date |
---|---|

Solve for a constant in an equation | Jan 14, 2016 |

Solving this set of trigonometric equations | Aug 18, 2015 |

Questions on Trigonometric equation solving | Apr 5, 2015 |

Solve trigonometric equation | Oct 9, 2011 |

Solving trigonometric equation | Jan 30, 2009 |

**Physics Forums - The Fusion of Science and Community**