Solving an Equation using the Gravitational Constant

AI Thread Summary
In the discussion, participants clarify that 0.001 is added to convert grams to kilograms, as there are 1000 grams in a kilogram. The formula for escape velocity is provided, indicating that it involves the gravitational constant and the mass of the object. To solve for escape velocity, one should ensure that the units cancel appropriately to yield a velocity unit. The next step involves substituting values into the equation while checking for unit consistency. There is a suggestion that converting all measurements to SI units before calculations may simplify the process.
Thrawn
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Homework Statement


Why, in the second step of the question, is 0.001 added to the right side?

Part 2. In the equation Ve = sqrt 2(6.6742 x 10^-11 N m^2 / kg^2 (12.1kg))/0.106780959m

I'm trying to calculate the escape velocity of an object, and have figured out everything up to this point. Now, I have no idea how to procede. Do I cancel things out? Do I add a number to both sides?


Homework Equations


G2.gif





The Attempt at a Solution



For the first part, I would guess that it is simply to... well I have no idea...
 
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Thrawn said:

Homework Statement


Why, in the second step of the question, is 0.001 added to the right side?
200 is multiplied by 0.001 to convert it from grams into kilograms, since there are 1000g in 1kg-- does that answer your question?
Part 2. In the equation Ve = sqrt 2(6.6742 x 10^-11 N m^2 / kg^2 (12.1kg))/0.106780959m

I'm trying to calculate the escape velocity of an object, and have figured out everything up to this point. Now, I have no idea how to procede. Do I cancel things out? Do I add a number to both sides?

I don't get what you mean by this!
 
cristo said:
200 is multiplied by 0.001 to convert it from grams into kilograms, since there are 1000g in 1kg-- does that answer your question?


I don't get what you mean by this!

The formula to calculate escape velocity is:

Ve = sqrt 2(mu)/r

Where r is the distance from the denter of the object to be escaped from, and mu is the Gravitational Constant multiplied by the mass of the object to be escaped from.

All sai and done, this gives an equation of: Ve = sqrt 2(6.6742 x 10^-11 N m^2 / kg^2 (12.1kg))/0.106780959m

What would be the next step in solving this?
 
You just need to check that the units cancel to give a unit of velocity (noting that N=kg m s-2), then compute the numerical answer.
 
cristo said:
You just need to check that the units cancel to give a unit of velocity (noting that N=kg m s-2), then compute the numerical answer.


So would the next step be: Ve = sqrt 2(6.6742 x 10^-11 kg m/s^2 m^2/kg^2 (12.1kg)/0.106780959m ?

If not, then what?
 
Yes, now check that the units cancel and compute the numerical answer.

Personally, I think the method of keeping the units in during the calculation is very confusing, and that you should convert everything into SI units before plugging into the equation. But ,if that's how you've been taught to answer the question, then I guess you should do it that way.
 
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