Max0007 said:Homework Statement
Hello,
This factorized function F(x,y) = (x^2+y^2)(x+y)(x-y)(x+2y)
The question I need to answer is solve F(x,y) = 0 for y = 1
0 = (x^2+1^2)(x+1)(x-1)(x+2(1))
would it be this? or first I do f(x,y) = 0 then do it again with y = 1?
Homework Equations
0 = (x^2+1^2)(x+1)(x-1)(x+2(1))
The Attempt at a Solution
This is what I go S = {-2,-1,1}Dick said:It's just fine to solve that equation with y=1. Can you solve it?
Max0007 said:This is what I go S = {-2,-1,1}
is this correct?
Solving an equation means finding the value(s) of the variable(s) that make the equation true.
Solving an equation allows us to find the specific value(s) of the variable(s) that satisfy the equation, which can help us better understand relationships between different quantities and make predictions or solve problems.
To solve an equation with two variables, you can use algebraic manipulation to isolate one variable on one side of the equation and then solve for its value. Once you have the value of one variable, you can substitute it into the equation to solve for the other variable.
The process for solving F(x,y) = 0 for y = 1 involves substituting y = 1 into the equation and then solving for the value(s) of x that satisfy the equation. This can involve algebraic manipulation and possibly using a calculator or other tools to solve for x.
Yes, there can be more than one solution to an equation. This means that there may be multiple values of the variable(s) that satisfy the equation and make it true. It is important to check the solutions you find by substituting them into the original equation to make sure they are valid.