Solving an Integral: Is My Attempt Right?

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SUMMARY

The integral discussed is \(\int \frac{x}{\sqrt{2x-20}} \, dx\). The user attempted a substitution \(u = 2x - 20\), leading to the expression \(\int \frac{u+20}{2u^{1/2}} \, du\). The correct integration results in \(\frac{1}{6}(2x-20)^{3/2} + 10(2x-20)^{1/2} + C\), confirming the user's approach was fundamentally correct, but they misinterpreted the variable transformation.

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Homework Statement



[tex]\int x/2x-20)^(1/2)[/tex]

The Attempt at a Solution



I did u sub got the [tex]\int (u+20)/(2u^1/2)du[/tex] which became (1/6)(2x-20)^(3/2) + 10(2x-20)^(1/2)

Is this right? What am i doing wrong if it is not.
 
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Do you mean
[tex]\int\frac{u+20}{2u^{1/2}}du[/tex]
If so that is the same as
[tex]\int [(1/2)u^{1/2}+ 10u^{-1/2}]du[/tex]
I don't see how you would get 2x-20- since there is no x in the original integral!
 

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