Solving an IVP using a direction field I think

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SUMMARY

The discussion focuses on solving an initial value problem (IVP) defined by the differential equation x' = x - t, specifically finding values of x0 such that the solution passes through the points (4,0) and (6,0). The user expresses confusion about using the DFIELD applet for visualizing direction fields and whether to solve the problem by hand. The correct approach involves inputting the equation into the DFIELD applet, which requires understanding how to manipulate the equation for proper visualization. The initial values derived are -4 for (4,0) and -6 for (6,0).

PREREQUISITES
  • Understanding of differential equations, specifically first-order linear equations.
  • Familiarity with the concept of initial value problems (IVPs).
  • Basic knowledge of using software tools for mathematical visualization, such as DFIELD.
  • Proficiency in manipulating equations and using integrating factors.
NEXT STEPS
  • Learn how to effectively use the DFIELD applet for visualizing direction fields.
  • Study the method of integrating factors for solving first-order linear differential equations.
  • Explore the concept of direction fields and their applications in solving differential equations.
  • Practice solving initial value problems with different differential equations to build confidence.
USEFUL FOR

Students studying differential equations, educators teaching calculus concepts, and anyone looking to enhance their skills in solving initial value problems using software tools.

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Homework Statement


Instructions: You will need to use software for these problems. The goal is to find a number x0 such that the solution to the initial value problem x'=ƒ(t,x) x(0)=x0 passes through the given "target". Attach figures that you used to answer the problems.

1. Consider the differential equation x'=x-t
(a) Find x0 such that the solution of the initial value problem x'=x-t, x(0)-x0 will pass through (4,0).

(b) Find x0 such that the solution of the initial value problem x'=x-t, x(0)-x0 will pass through (6,0).


Homework Equations





The Attempt at a Solution



So there are many places here where I "freeze up" before I really attempt to solve this problem. One is because I don't even know how to use the software they want us to use. I think it's something similar to MATLAB but this is only to visualize direction fields. The link we were given was

http://math.rice.edu/~dfield/dfpp.html

I went there but I wasn't sure how to get it to look like anything other than the default. I wrote the equation x'=x-t into the field for differential equation and hit graph but nothing happened.

I just want to double check, I am not supposed to start solving it by hand right? I tried to...

x'=x-t

subtract x to the other side since it is a linear equation, no higher powers involved.

x'-x=-t

Using the integrating factor e∫-1dt=e-t

now if i multiply everything by e-t

e-tx'-e-tx=-te-t

but the second term, the one containing the x to the power of one, does not contain any t term that I can use with x and x' so that I can use the product rule in reverse. This leads me to think it is not a linear equation? which then leads me back to my first question...am I supposed to not do anything by hand?

When I pull up the "DFIELD" applet there is a field for me to put my differential equation in but it is set to take in an x' by default so should I assume I should just put it into the field?

I am still not comfortable enough to look at these problems and visualize what it asks. I don't feel like I understand what goes on in every case. It's like I am writing an essay, and I am choosing to include long and sophisticated words that while I may know their definition if singled out of context, I have no idea when and where to use it.

Any help is appreciated.
 
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When t= 4 and x= 0, x'= x- t= 0- 4= -4. That is the initial value of x' you need.

Similarly, for the second problem, with t= 6 and x= 0, x'= 0- 6= -6.
 

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