Solving Calculus Derivatives at a Specific Point

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    Calculus
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Homework Help Overview

The discussion revolves around finding the derivative of the quotient of two functions at a specific point using the Quotient Rule in calculus.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the Quotient Rule and share links to external resources for clarification. Some express uncertainty about the question's intent and seek guidance on how to approach the problem.

Discussion Status

There is an ongoing exploration of the Quotient Rule and its application to the given problem. Some participants have offered guidance and resources, while others have expressed their confusion regarding the question's purpose.

Contextual Notes

Participants note that the question is intended to assess knowledge of differentiation rules, specifically the Quotient Rule, and some express concern about the appropriateness of the question in a homework context.

tee yeh hun
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F(5) =1 , F'(5)=6, G(5)=-3 and g'(5)=2 Find the value

([tex]\frac{f}{g}[/tex])'(5) = ?

Answer is -[tex]\frac{20}{9}[/tex].

Can anyone shows the way to solve this?
 
Last edited:
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http://en.wikipedia.org/wiki/Quotient_rule" helps?
 
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i guess not...
 
You need to apply the Quotient Rule for derivatives,
[tex]\frac{d}{dx} \left(\frac{f(x)}{g(x)}\right) = \frac{g(x)f'(x)-f(x)g'(x)}{(g(x))^2}[/tex]

You're given certain information on two functions. How can you use that information to find the derivative of the quotient of the two functions?

This is obviously a homework question. We won't solve your homework for you, only point you in the right direction.
 
sorry for posting the wrong place, will change the place.

I am not sure why they ask such a question.

I am not expecting others to do my homework but only wants other people to show me the direction.
 
tee yeh hun said:
I am not sure why they ask such a question.

These questions are designed to test one's knowledge of the various rules of differentiation, in this case the quotient rule.

All you really need to do is plug in the proper values.
 
oh!... i got it already , thank you
 

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