Solving Circuits with Multiple Cells & Capacitors

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To determine the equivalent capacitance, voltage, and charge in circuits with multiple batteries and capacitors, start by simplifying the circuit by combining capacitors in series and parallel. Each set of series capacitors can be reduced to a single capacitor value, which simplifies the analysis significantly. After reducing series capacitors, repeat the process for parallel sets, further decreasing the number of capacitors in the circuit. This method not only streamlines calculations but also clarifies the overall circuit structure. Understanding these simplifications is essential for analyzing complex circuits effectively.
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For the circuit posted (or any similar circuits really), how do we simplify to determine the equivalent capacitance, voltage and charge of the system? With multiple batteries, how does this affect the circuit? Sorry for not posting in the homework section. It's just that I don't really need an answer and would like insight in general on how circuits with multiple cells and numerous capacitors (that look like they are in both parallel and series, with different capacitors) are understood. I'm sure an explanation of how to solve this example would help, but it's not necessary and I thought it would be good to have as a reference.Thank you!
 

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hi there

initially you can simplify it by working out the single cap values for any that are in series or parallel
there will for a start reduce the number of caps ( would be just the same if they were all resistors instead of caps)

so for a start, every obvious set of series cap reduce that to a single cap and redraw the circuit accordingly
that's immediately going to get rid of ~ 8 caps
then do the same for all parallel sets and redraw

cheers
Dave
 
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