Solving Circular Motion for Two Bodies Separated by Distance A

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The discussion focuses on a problem involving two bodies separated by a distance A, where one body moves with a velocity v perpendicular to the line connecting them. The key conclusion is that if both bodies maintain the same speed v, the body moving perpendicular cannot catch the other due to the nature of their motion. The time t for the catch-up scenario cannot be determined as the directions of motion are incompatible for the specified conditions.

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two bodies seprated by A distance a then one body starts moving with a velocity v in the direction prependicular to A then the other body starts moving in order to catch the other one at the same time with constant velocity v and catches the other boy in a time t where t is?



as clearly is doesn't state the direction of "other body" so i tried a lot of ways but in all the term t just cancels out
 
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If they are both moving with constant velocity, then their directions can't change. Perhaps you mean constant speed?

If they both have the same speed, v, then there is no way that one body can catch the other if they have an initial separation and one body's velocity is perpendicular to the other.
 
lemme just quote the original question..

two boys standing at the ends A and B of s ground, where AB = a. the boy at B starts running in a direction perpendicular to AB with velocity v. the boy at A starts running simultaneously with constant velocity v and catches the other boy in a time t, where t is
 

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