Solving Circular Motion for Two Bodies Separated by Distance A

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Two bodies are separated by distance A, with one moving perpendicularly at velocity v while the other moves to catch up with the same velocity v. The discussion highlights that if both bodies maintain constant speeds and their directions remain unchanged, the body moving perpendicularly cannot be caught. The initial separation means that the body moving towards the other cannot close the gap if both are traveling at the same speed. The question raises confusion about the direction of movement and the implications of constant velocity versus constant speed. Ultimately, the scenario suggests that one body cannot catch the other under these conditions.
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two bodies seprated by A distance a then one body starts moving with a velocity v in the direction prependicular to A then the other body starts moving in order to catch the other one at the same time with constant velocity v and catches the other boy in a time t where t is?



as clearly is doesn't state the direction of "other body" so i tried a lot of ways but in all the term t just cancels out
 
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If they are both moving with constant velocity, then their directions can't change. Perhaps you mean constant speed?

If they both have the same speed, v, then there is no way that one body can catch the other if they have an initial separation and one body's velocity is perpendicular to the other.
 
lemme just quote the original question..

two boys standing at the ends A and B of s ground, where AB = a. the boy at B starts running in a direction perpendicular to AB with velocity v. the boy at A starts running simultaneously with constant velocity v and catches the other boy in a time t, where t is
 
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