- #71

ChiralSuperfields

- 1,281

- 136

Thank you for your reply @haruspex!haruspex said:Since ##F_{net}=T\hat i - F_f\hat i##, ##W_{net} =( T\hat i - F_f\hat i)\cdot (r+\frac I{mr})\theta\hat i=(T-F_f) (r+\frac I{mr})\theta##.

Btw, just noticed that there’s a false assumption we all may have been making implicitly, that the friction acts to the left. In fact, it will act to the right. But the equations are fine, it's just that the value of F_{f}will be negative.

So from that equation static friction contributes to the net work (so dose do work actually?). Assuming that ## T > F_f## then the ## W_{net} > 0##

Many thanks!