Solving Derivative dy/dx: y, sin(xy) + 1 = cos x

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The discussion focuses on solving the derivative dy/dx for the equation (e^y) cos(x) = 1 + sin(xy). Participants emphasize the use of implicit differentiation and the chain rule to derive the correct expression. The initial attempt at differentiation yielded an incorrect result, highlighting the importance of following proper differentiation techniques. The correct approach involves differentiating both sides of the equation while applying the chain rule appropriately.

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skyhawk714
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1. Find the derivatie of y, dy when e/\(y) cos x=1 + sin (xy)
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dx

2. I don't know of any Relevant equations


3. The first time i tried the problem i got e/\(y) cos X+ y cos (xy)
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e/\(y) sin x- x cos (xy)

but i know that's not right...how do i even do a problem like this?
 
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You are trying to use implicit differentiation to find dy/dx given (e^y)*cos(x)=1+sin(xy), right? Your answer has the right sort of general form, but it's not correct. Differentiate both sides of (e^y)*cos(x)=1+sin(xy) using the chain rule and show the steps you did to get your answer.
 
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