Solving Double Slit Question with 16.81x10^-19J Energy

[physics_06er]

Hello

Could someone please help me with this question,,I have no idea how to work it out and have looked through my textbook/notes and arrrr still can't do it...

A beam of photons encounters a double slit that has a separation distance d = 34.0 μm. Note: the diagram is not drawn to scale...(the diagram just shows a slit with a detector array 'x' meters away)

a)...if a single photon in the beam has an energy of 16.81x10^-19J what is it's energy in eV?

I calculated that to be 10.5eV but then its the next one I can't do as I have no other info. besides separation distance and energy!

b) What is it's wavelength?
??

Any help would be much appreciated
Thank you
physics_06er

 

[maverick280857]

You have to show your work here first.

The two questions are very easy. Go through your Modern Physics textbook/course notes again...you're missing something.

 

[Chi Meson]

I think this is enough of a hint: there was a guy named Max Planck...

 

[Hootenanny]

I think this is enough of a hint: there was a guy named Max Planck...

And he lived in a land far far away...

~H

 

[Chi Meson]

And he lived in a land far far away...

~H

Then one day, the morning after the ultraviolet catastrophe erupted...
...
nah!

Sorry, back to the thread. What is the thing Planck is most remembered for?

 

[Hootenanny]

Then one day, the morning after the ultraviolet catastrophe erupted...
...
nah!

Yes, I think this thread has become a little tangental. We should wait for the OP to return before we continue our story

~H

 

[physics_06er]

Hi there

Thanks for the help

so I just found Freq using E=hf and then wavelength using c=f.lamda coming up with 1.18e-7m

Thanks again
physics_06er

...You guys can carry on your story if you wish

 

[physics_06er]

Hello there...so I worked out how to to the angle question...however can someone pls check my working...by the way I made a mistake in my first post the separation distance is 38.0micrometres

...so to find the freq. i used E/h ..16.81e-19/6.63e-19=2.535444947Hz then I went 3e8/2.535444947 and got 118322427.1 (its in meters right)..well the answer says 0.118nm? What have I done wrong...

Next for the angle question i used dsintheta=(m+0.5)lamda and got an angle of 0.089...however this is when I use the answer they have given me...someone please tell me where I have gone wrong?

 

[physics_06er]

seems my angle question was deleted...but the question was if the detector array is placed 3.0m behind the double slit determine:...the angle m=0 destructive interference which is the one I have answered above---and also this one I hav NO idea how to do...determine the distance above the center of the interference pattern..I don't even know what they are asking?

 

[tyco05]

...so to find the freq. i used E/h ..16.81e-19/6.63e-19=2.535444947Hz then I went 3e8/2.535444947 and got 118322427.1 (its in meters right)..well the answer says 0.118nm? What have I done wrong...

re-check your value for h... I haven't done the calculations, but it should put you in the right ball park