Solving expected value problem with logistic function

AI Thread Summary
The discussion centers on solving an expected value problem involving a logistic function, where the goal is to determine the variable x that achieves a desired expected value z. The expected value is calculated using a probability of success based on the logistic function, leading to a complex equation that combines rewards and losses. Attempts to find an explicit solution in Matlab were unsuccessful, indicating the need for alternative methods. Participants are exploring simplification strategies and potential solutions for the probability function p(x). The conversation emphasizes the challenge of deriving a solution for the expected value using the logistic function framework.
tlonist
Messages
1
Reaction score
0
I have an expected value problem where z is a desired expected value and I want to reach and x is an amount I can vary.

There is a probabilty of success based on a logistic function ρ(x) with a reward of λx and failure with a probability of (1-ρ(x)) and loss of x. I am trying to solve for the correct value of x to reach an expected value z.

So:

z = p(x) \lambda x - (1-p(x)) x

z = \frac{\lambda x}{1+ e^{-a-bx} } + \frac{x}{1+ e^{-a-bx} } -x


I tried solving in Matlab but it says there is no explicit solution and I haven't been able to solve by hand.

What would be the next course of action to solve this? Is there a way to simplify?
 
Mathematics news on Phys.org
It looks as if ##p(x)=\dfrac{1}{1+e^{-a-bx}}## is a solution.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Thread 'Imaginary Pythagorus'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
Back
Top