Solving for a & b: Increasing GP Equations

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The discussion revolves around finding the values of a and b given two quadratic equations with roots in increasing geometric progression (G.P.). The roots of the first equation, x^2 - 3x + a = 0, sum to 3, while the roots of the second equation, x^2 - 12x + b = 0, sum to 12. Participants clarify that an increasing G.P. implies the common ratio is greater than 1, leading to the order x_1 < x_2 < x_3 < x_4. However, the initial equations alone are deemed insufficient to derive a and b without further analysis. The conversation emphasizes the need to explore the implications of the G.P. condition to solve the problem effectively.
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Homework Statement


If x_1,x_2 are the roots of x^2-3x+a=0 and x_3,x_4 are the roots of the equation x^2-12x+b=0 and x_1,x_2,x_3,x_4 are in increasing G.P., find a and b

Homework Equations



The Attempt at a Solution


x_1+x_2=3 \\<br /> x_1x_2=a \\<br /> x_3+x_4=12 \\<br /> x_3x_4=b

But these are not sufficient to find a and b. Also what is meant by an increasing G.P.?
 
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utkarshakash said:

Homework Statement


If x_1,x_2 are the roots of x^2-3x+a=0 and x_3,x_4 are the roots of the equation x^2-12x+b=0 and x_1,x_2,x_3,x_4 are in increasing G.P., find a and b

Homework Equations



The Attempt at a Solution


x_1+x_2=3 \\<br /> x_1x_2=a \\<br /> x_3+x_4=12 \\<br /> x_3x_4=b

But these are not sufficient to find a and b. Also what is meant by an increasing G.P.?
G.P. = Geometric Progression

http://en.wikipedia.org/wiki/Geometric_progression
 
utkarshakash said:
But these are not sufficient to find a and b. Also what is meant by an increasing G.P.?

It means that the common ratio of the GP is greater than 1.
 
Pranav-Arora said:
It means that the common ratio of the GP is greater than 1.

This means that x_1&lt;x_2&lt;x_3&lt;x_4
But what is the use of this in my question?
 
utkarshakash said:
This means that x_1&lt;x_2&lt;x_3&lt;x_4
But what is the use of this in my question?

Ignoring that detail for the moment, simply try answer the question and then you'll see.
 
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