Solving for C in 1.41 = |(1+1.10iC)/(1+0.1iC)|

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Homework Help Overview

The discussion revolves around solving for the variable C in the equation 1.41 = |(1+1.10iC)/(1+0.1iC)|, which involves complex numbers and their magnitudes.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore methods for manipulating the equation, such as multiplying by a conjugate to simplify the expression. Questions arise regarding the definition of the magnitude of complex numbers and how it applies to the problem at hand.

Discussion Status

Some participants have offered guidance on using properties of complex numbers to approach the problem, while others express uncertainty about how these suggestions will lead to a solution for C. Multiple interpretations of the problem and potential methods are being explored.

Contextual Notes

There is a mention of a related problem involving a different variable, x, which is used as a comparison to help understand the original equation. The discussion reflects a lack of consensus on the best approach to take.

Dirac8767
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I have the following equation below but i am unsure about the method of finding the variable C. Sorry if its hard to read.

1.41 = |(1+1.10iC)/(1+0.1iC)|

Many thanks
 
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Maybe multiplying by (1 - 0.1iC)/(1 - 0.1iC) inside the magnitude bars will make your life easier :)
 
Do you know how the magnitude of a complex number is defined?

If z = x + iy, then the magnitude of z is

|z| = \sqrt{zz^\ast} = \sqrt{x^2 + y^2}

where z^\ast = x - iy. One can show that if z and w are complex numbers, then |z/w| = |z|/|w|. You can use this fact to help solve your problem. (This method won't require CompuChip's hint).
 
Mute said:
Do you know how the magnitude of a complex number is defined?

If z = x + iy, then the magnitude of z is

|z| = \sqrt{zz^\ast} = \sqrt{x^2 + y^2}

where z^\ast = x - iy. One can show that if z and w are complex numbers, then |z/w| = |z|/|w|. You can use this fact to help solve your problem. (This method won't require CompuChip's hint).

Okay, but I am still struggling to see how that will help me solve for C
 
Dirac8767 said:
Okay, but I am still struggling to see how that will help me solve for C

If I gave you the problem

A = \sqrt{\frac{a^2 + d^2x^2}{b^2 + c^2x^2}}

could you solve for x?

My advice helps you make your expression look like this one. If you can solve this one above, you can solve your problem. Can you see how to get from your original expression to a form looking like the one above using the fact that for complex numbers z and w, |z/w| = |z|/|w| and using the definition of the magnitude of a complex number, |z| = |x + iy| = \sqrt{x^2 + y^2}?
 

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