Solving for Final Velocities and Min Length of m2

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The discussion focuses on calculating the final velocities of two objects, m1 and m2, where m1 initially moves at 10 m/s and m2 is stationary with a kinetic friction coefficient of 0.2. Using conservation of momentum, the final velocity of both objects is determined to be 4 m/s after m1 slows down. However, the minimum length of m2 remains unresolved, as the participants struggle to establish the relationship between the frictional forces and the dimensions required for m2. The problem emphasizes the need for further analysis to derive the minimum length based on the forces acting on m2. Overall, the thread highlights the application of momentum conservation in solving for final velocities while leaving the length calculation open for discussion.
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Homework Statement


(Diagram of problem is given in attachment)
m2 is stationary
The coefficient of kinetic friction on m2 is 0.2 while the ground below m2 has a coefficient of friction of 0.

a) Find the final velocity of both objects if m1 moves at the same v as m2

b)Find the minimum length of m2

Homework Equations



mv = p (Momentum)

The Attempt at a Solution



m1v1 = m1v1' + m2v1'
m1v1 = 50v1'
(10)(20) = 50v1'
200/50 = v1'
v1 = 4m/s

I was able to calculate the final velocity of the two objects using conservation of momentum but I have no clue how to calculate the minimum length of m2.
 

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m1 is slowed down from 10 to 4 meters per second on m2 while m2 is speeding up from 0 to 4 m/s. At that point they are moving together.
 
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