Solving for indefinite integral

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SUMMARY

The discussion focuses on solving indefinite integrals, specifically the problems ∫(t^3/2 + 2t^1/2 - 4t^-1/2)dt and ∫sqrt(t)(t^2 + t - 1)dt. The first integral is correctly approached by applying the power rule for integration, yielding 2/3t^5/2 + 4t^3/2 - 8t^1/2 + c. For the second integral, participants suggest expanding the expression by multiplying sqrt(t) with the polynomial (t^2 + t - 1) to simplify the integration process.

PREREQUISITES
  • Understanding of integral calculus, specifically the power rule for integration.
  • Familiarity with polynomial expressions and their manipulation.
  • Knowledge of fractional exponents and their properties.
  • Basic algebra skills for simplifying expressions.
NEXT STEPS
  • Practice solving indefinite integrals using the power rule for various polynomial functions.
  • Learn techniques for expanding and simplifying expressions before integration.
  • Explore the application of integration by substitution for more complex integrals.
  • Study the properties of fractional exponents and their implications in calculus.
USEFUL FOR

Students studying calculus, particularly those learning about indefinite integrals and integration techniques, as well as educators looking for examples to illustrate these concepts.

4littlepigs
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Homework Statement



My daughter at college asked me to help her with these but it's been years since I've done them. I said I would try and then look over what she comes up with so any help would be great not so I can give her the answers but so I can tell her whether or not she on the right track and help her try to find it!

Problem 1
∫(t^3/2 + 2t^1/2 -4t^-1/2)dt=
∫t^3/2(dt) + 2∫t^1/2(dt) -4∫t^-1/2(dt)=
2/3t^5/2 +(2)(2)t^3/2 -(4)(2)t^1/2 +c=
2/3t^5/2+4t^3/2-8t^1/2+c

Am I anywhere near right with this one?

And the second one is:
∫sqrt(t)(t^2+t-1)dt
but I have no idea where to go with it...

Thanks to any and all that help and for any help you can give.


The Attempt at a Solution


What I have so far are above!
 
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The integral of t^n is t^(n+1)/(n+1). Apply that to t^(3/2) e.g. You get t^(5/2)/(5/2)=(2/5)*t^(5/2). Try and check your expression again. For the second one just multiply it out. E.g. sqrt(t)*t^2=t^(1/2)*t^(2)=t^(2+1/2)=t^(5/2). Now you've got the same kind of fractional powers as in the first part. You can also make your expression clearer with more parentheses. 2/3t^5/2 can be interpreted lots of different ways. Like ((2/(3t))^(5))/2.
 

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