Solving for Median of P(r) with Exponential Terms

Click For Summary
SUMMARY

The discussion focuses on solving for the median of the function P(r) = 1 - (2r² + 2r + 1)e^(-2r). The user correctly identifies that P(r) is the integral of its derivative, p(r), and seeks to find the value of r that satisfies the equation 1 - (2r² + 2r + 1)e^(-2r) = 0.5. The conclusion is that this equation requires numerical methods for a solution due to the complexity introduced by the exponential term.

PREREQUISITES
  • Understanding of calculus, specifically integration and derivatives.
  • Familiarity with exponential functions and their properties.
  • Knowledge of numerical methods for solving equations.
  • Experience with mathematical software or programming languages for numerical computation.
NEXT STEPS
  • Learn numerical methods for root-finding, such as the Newton-Raphson method.
  • Explore the use of Python libraries like NumPy and SciPy for numerical integration and solving equations.
  • Study the properties of exponential decay functions in mathematical modeling.
  • Investigate how to visualize functions and their integrals using graphing tools.
USEFUL FOR

Students and professionals in mathematics, physics, and engineering who are working on problems involving integrals and numerical solutions, particularly those dealing with exponential functions.

apiwowar
Messages
94
Reaction score
0

Homework Statement



P(r) = 1-(2r2+2r+1)e-2r

i know that p(r) is just the derivative of P(r)

to find the median i would just integrate from o to r and set that equal to .5
but when you integrate youre just going back to P(r) from 0 to r

so i get

1-(2r2+2r+1)e-2r = .5

how would i go about solving this since i have the r's inside the parentheses and then the e raised to the -2r?
 
Physics news on Phys.org
You would solve it numerically.
 

Similar threads

Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 87 ·
3
Replies
87
Views
4K
Replies
9
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
6
Views
3K