Solving for variables using 3 different equations (simultaneous equations)

AI Thread Summary
To solve for variables A, T1, and T2 using the given simultaneous equations, start by isolating A in the first equation, resulting in A = (245 - T1) / 25. Next, express T2 in terms of A from the second equation, yielding T2 = 98 + 10A. Substitute these expressions for T1 and T2 into the third equation to solve for A. Once A is determined, use it to find the values of T1 and T2. Proper substitution and careful calculations are essential to avoid errors in the final results.
ReMa
Messages
10
Reaction score
0

Homework Statement



Solve for A, T1 and T2.

Equa 1) T1 + 25.0a = 245
Equa 2) T2 − 10.0a = 98.0
Equa 3) T1 − T2 − 80.0a = 78.4

Homework Equations



As above.

The Attempt at a Solution



I isolated a in the first equation:

a = (245-T1)/25

and T2 in the second equation:

T2 = 98 + 10(245-T1)/25

And when subbing these values in I end up getting an answer WAY off for T1. Any help would be highly appreciated as I feel like I'm just doing improper calculations with my fractions...
 
Physics news on Phys.org
Solve for T1 in equation 1 and for T2 in equation 2. Both T1 and T2 will be in terms of a. Substitute for T1 and T2 in equation 3, and solve for a. After you get a, you can get T1 and T2.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top