Solving for X When it Appears Twice

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SUMMARY

The discussion focuses on solving an algebraic equation to determine the hourly rate (x) for an employee based on their weekly salary (c) and hours worked at different rates. The equation is structured as (a*x) + (b*1.5x) = c, where 'a' represents regular hours and 'b' represents overtime hours. The solution provided isolates x, yielding the formula x = c / (a + 1.5b). This formula allows for the calculation of the hourly rate given known values for a, b, and c.

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Dowarner
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I've run into my first real life algebra problem and my high school algebra memory isn't cutting it.

Here's the problem:

To fit budget, an employee of a company needs to earn a known weekly salary (c)
The company's boss needs to calculate the employee's regular hourly rate (x) based on the number of hours they work in the week to get to that salary
Hours are worked at two different rates, however. Regular hours (a) are worked at the rate of "x" and overtime hours are worked at "1.5x".

This leaves us with the equation of:
(a*x) + (b*1.5x)=c

I need to isolate for x as a,b and c are all known.

Please help!
 
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Hi Dowarner and welcome to MHB! :D

Your problem appears to be set up correctly. Here's what I have for your request:

$$ax+1.5bx=c$$

$$x(a+1.5b)=c$$

$$x=\frac{c}{a+1.5b}$$
 

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