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Adjoint
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[EDITED. Thanks to Doc Al, Tanya Sharma and dauto]
A ball is dropped from rest from the top of a building of
height h. At the same instant, a second ball is projected vertically
upward from ground level, such that it has zero speed when it
reaches the top of the building.
(A) At the time when the two balls pass each other -
which ball has the greater speed, or do they have the same speed?
(B) Where will the two balls be when they are alongside each
other: at height h/2 above the ground, below this height, or above
this height?
Equations of 1D motion for a constant acceleration of -g
First here is the diagram I drew:
Now for part (A):
I suppose that the second ball was thrown up with velocity v0
And the balls pass each other at time t
So for the first ball v = -gt
And for the second ball v = v0 -gt
So speed of the first ball |-gt|
Speed of the second ball |v0 -gt|
Now which one is greater? How can I tell??
I shall post my attempt for second part later but someone please help me deal with this.
Thanks in advance!
Homework Statement
A ball is dropped from rest from the top of a building of
height h. At the same instant, a second ball is projected vertically
upward from ground level, such that it has zero speed when it
reaches the top of the building.
(A) At the time when the two balls pass each other -
which ball has the greater speed, or do they have the same speed?
(B) Where will the two balls be when they are alongside each
other: at height h/2 above the ground, below this height, or above
this height?
Homework Equations
Equations of 1D motion for a constant acceleration of -g
The Attempt at a Solution
First here is the diagram I drew:
Now for part (A):
I suppose that the second ball was thrown up with velocity v0
And the balls pass each other at time t
So for the first ball v = -gt
And for the second ball v = v0 -gt
So speed of the first ball |-gt|
Speed of the second ball |v0 -gt|
Now which one is greater? How can I tell??
I shall post my attempt for second part later but someone please help me deal with this.
Thanks in advance!
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