Solving Fuzzy Dice Question: Finding Car Acceleration

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A pair of fuzzy dice weighing 0.0820 kg hangs at a 5.00° angle from the vertical as a car accelerates. To find the car's acceleration, the discussion emphasizes using Newton's second law, F=ma, and considering the forces acting on the dice. The acceleration of the dice is equal to that of the car, simplifying the problem. After some initial confusion, the participant successfully solves the problem, realizing it was less complicated than anticipated. The conversation highlights the importance of understanding the relationship between forces and acceleration in physics.
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Homework Statement



A 0.0820 kg pair of fuzzy dice is attached to the rearview mirror of a car by a short string. The car accelerates at a constant rate, and the fuzzy dice hang at an angle due to the car's acceleration. If the dice hang at 5.00° from the vertical as the car accelerates, what is the acceleration of the car?

Homework Equations



F=ma, trig functions.

The Attempt at a Solution



So I have the freebody diagram with mg pointing down, Fn pointing up, and Fa pointing downward at a 5 degree angle from the y axis. I know how to find mg of course, but now I'm just lost. Please help me at least wave my hands at this thing...
 
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Welcome to PF!

Hi sheepcountme! Welcome to PF! :smile:

Hint: the acceleration of the dice is the same as that of the car.

So use good ol' Newton's second law (vector form), Ftotal = ma. :wink:
 
Thank you!

I figured it out! What a relief! I was making it much more complicated than it needed to be!
 

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