Solving geodesic equations on the surface of a sphere

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SUMMARY

The discussion focuses on solving geodesic equations on the surface of a sphere with radius 'a' using spherical coordinates. The derived equations for the angles T and P are: d²T/ds² - (sinTcosT)(dP/ds)² = 0 and d²P/ds² - 2cotT(dT/ds)(dP/ds) = 0. The user seeks assistance in finding a particular solution to these differential equations, indicating a need for guidance in solving such mathematical problems.

PREREQUISITES
  • Understanding of spherical coordinates and their representation.
  • Familiarity with differential equations and their solutions.
  • Knowledge of geodesic equations in differential geometry.
  • Basic proficiency in calculus, particularly in second-order derivatives.
NEXT STEPS
  • Study methods for solving second-order differential equations.
  • Explore the concept of geodesics in differential geometry.
  • Learn about specific solutions to differential equations, such as particular and general solutions.
  • Investigate numerical methods for approximating solutions to complex differential equations.
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Students and researchers in mathematics, physics, and engineering who are working on problems involving geodesics and differential equations on curved surfaces.

WannabeNewton
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Homework Statement



Find the geodesics on the surface of a sphere of radius a by:
(a) writing the geodesic equations for the spherical coordinates given by:
x = rsinTcosP
y = rsinTsinP
z = rcosT

for T and P(the r - equation can be ignored as a = constant);
(b) exhibit a particular solution of these two equations; and (c) generalize (b).

Homework Equations


Geodesic equation in general form (sorry don't know how to use LaTeX)


The Attempt at a Solution


Ok so I did part (a) and ended up with the equations for T and P as follows:

d^2T / ds^2 - (sinTcosT) * (dP / ds)^2 = 0
d^2P / ds^2 - 2cotT * (dT / ds) * (dP / ds) = 0

I am terrible at solving differential equations and basically have no idea what to do from here to find a particular solution. I was hoping someone could guide me through it.
 

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