Solving Inequality Problem: (|a|+|b|≥2(|c|+|d|))

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The discussion revolves around the inequality |a| + |b| ≥ 2(|c| + |d|) and its implications for proving (c + a)² + (d + b)² ≥ c² + d². Participants express difficulty in deriving a proof for the stronger form of the inequality, despite initial thoughts that it might be straightforward. One contributor mentions achieving a weaker result by assuming |b| ≥ |a| and |c| ≥ |d|, but acknowledges this approach sacrifices generality. The challenge remains unsolved, with a consensus that the problem is intriguing yet complex. The thread highlights the need for further exploration of the inequality's implications.
drago
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Hi,
I would appreciate some ideas on the following problem:

We are given the inequality:
(1)
|a| + |b| >= 2(|c| + |d|)

Can we conclude that:
(2)
(c + a)^2 + (d + b)^2 >= c^2 + d^2 ?

a, b, c, d are real.

I can prove (2) if (1) is in the form: |a| + |b| >= 4max(|c|,|d|), but the above is stronger.

Thank you.
drago
 
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i feel its true
its seems so easy but at 12.30 midnight i cannot think of anything! :frown:

-- AI
 
i feel its true
its seems so easy but at 12.30 midnight i cannot think of anything!

Yep I looked at it for a few minutes late last night and thought it looked easy but couldn't come up with much. I got another weaker result pretty easy but then decided to leave it for someone else.

BTW, I got the weaker result by assumming (without loss of generality) that |b| >= |a|. I then found that if I made the additional imposition that |c|>=|d| then I was able to prove the desired result pretty easily . This however definitely does give a loss of generality and hence a weaker result.
 
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