Solving initial velocity for falling object

AI Thread Summary
A stone is dropped from a 65 m high bridge, while a second stone is thrown downwards 2 seconds later, with both being heard hitting the water simultaneously. The relevant equation for the first stone's fall is d = vi*t + 1/2at^2, leading to the calculation of the time of fall for the first stone. The second stone's time of fall must account for the 2-second delay, and the initial velocity needs to be calculated accordingly. The speed of sound is not directly relevant to the calculation of the initial velocity of the second stone. The discussion emphasizes the importance of correctly applying the equations of motion to find the solution.
heythere1010
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Homework Statement


A stone is dropped from a bridge that is 65 m high. A second stone is thrown downwards 2 seconds later. Both the stones are heard hitting the water at the same time. The speed of sound is a constant 343 m/s. What is the initial velocity of the second stone.

Homework Equations


d=vi*t+1/2at^2

The Attempt at a Solution


65=0+1/2(-9.8)(t)^2

I know t-2 is used for the time of the second stone. I don't know which equations to use to make them equal.
 
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Your Relevant equation should suffice.

What value did you get for the time of fall for the first stone? So what must be the time (numeric value) that the second stone has to make the complete journey?
 
gneill said:
Your Relevant equation should suffice.

What value did you get for the time of fall for the first stone? So what must be the time (numeric value) that the second stone has to make the complete journey?
5.2. Do I just sub it into the second equation with t-2 and solve for initial velocity?
 
heythere1010 said:
5.2. Do I just sub it into the second equation with t-2 and solve for initial velocity?
Sure.
 
haruspex said:
Sure.
So the speed of sound is irrelevant?
 
heythere1010 said:
So the speed of sound is irrelevant?
The sounds of hitting the water were heard at the same time. Did they hit the water at the same time?
 
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