Solving Integration Problem: x^3*sqrt(x^2 +1)

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Homework Help Overview

The problem involves integrating the function x^3*sqrt(x^2 + 1), with a focus on substitution methods for solving the integral.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts various substitutions, including x^3 and x^2 + 1, but struggles with the resulting expressions. They express confusion about how to effectively apply substitution in this context.

Discussion Status

Some participants provide insights on potential substitutions, with one suggesting a transformation of the expression to facilitate integration. There is an exchange of ideas, but no consensus or resolution has been reached yet.

Contextual Notes

The discussion reflects the challenges of integrating the function using substitution, with participants questioning the effectiveness of their chosen variables and derivatives.

Molecular
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Homework Statement


Integrate x^3*sqrt(x^2 +1)


Homework Equations


The problem is to be solved by using substitution


The Attempt at a Solution


To be honest I'm at a complete stump here, I've tried most values for U. My first guess was x^3, since du/dx = 3x^2, but I can't substitute this into a root, can I? Choosing x^2+1 as U is also moot, as the derivative equals 2x and by substituting you are still left with x^2 on the left side of the equation.

So I thought perhaps the best idea would be to substitute all of sqrt(x^2 +1), as the derivative becomes x/(sqrt(x^2+1)) = x/u, but even then, I'm stuck with x^2 by substituting.

I've also tried all sorts of ways to rewrite the equation (such as x^3*(x^2+1)^0.5, however, with no luck). I'm really starting to wonder how I'm supposed to integrate this function by use of substitution, anyone got any thoughts that could push me in the right direction?

Thanks.
 
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Molecular said:
Choosing x^2+1 as U is also moot, as the derivative equals 2x and by substituting you are still left with x^2 on the left side of the equation.
Ah, but x^2 = u-1.
 
neutrino said:
Ah, but x^2 = u-1.

Aah of course, thank you for the help, my man. Seeing those little things is what makes integration fun, except of course, when you don't see them ;p.

Thanks again!
 
Have you considered writing [itex]x^3\sqt{x^2+ 1}[/itex] as [itex]x^2\sqrt{x^2+1} (x)[/itex] and letting u= x2[/sup[+ 1?
 

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