Solving Kirchoff's Rules - Circuit Analysis Practice

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The discussion revolves around solving a circuit analysis problem using Kirchhoff's Rules. The user attempted to determine the current in each resistor and the potential difference across a 200-ohm resistor by setting up a system of equations. However, their calculated values for the currents and potential difference did not match the answers provided in the textbook. A key error identified was in the handling of voltage signs in the equation involving 40V and 360V, which should have been treated as additive since they are in series. Correcting this mistake would align the user's results with the textbook answers.
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Homework Statement


In the circuit of Figure P28.28, determine the current in each resistor and the potential difference across the 200-ohm resistor.
FigP28.28.jpg



Homework Equations



Kirchoff's Rules
V=IR

The Attempt at a Solution



The way I did it was like this:
FigP28.28d.jpg

I set up a system of equations-
I1 + I2 + I3 + I4 = 0
- 40 V = I2 (80Ω) - I1 (200Ω)
40 V - 360 V = I3 (20Ω) - I2 (80Ω)
- 360 V - 80 V = I4 (70Ω) - I3 (20Ω)

And I get
I1=1.83 (for 200Ω)
I2=4.07 (for 80Ω)
I3=.30 (for 20Ω)
I4=-6.2 (for 70Ω)
Then I do V=IR to get the potential difference, which I got was 366 volts.

But in the back of the book, it says the answers are:
1.00 A up in 200Ω
4.00 A up in 70 Ω
3.00 A up in 80 Ω
8.00 A down in 20 Ω
200 V

What did I do wrong
 
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40 V - 360 V = I3 (20Ω) - I2 (80Ω)
The signs on the 40V and the 360V should be the same because they are in series - the potentials add.
 
thanks
 
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