Solving Linear Recurrence: ax_k+1 + bx_k + c

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The discussion revolves around solving the linear recurrence relation x_k+2 = ax_k+1 + bx_k + c, where c is not zero. Participants clarify that the term p can be derived as p = c / (a + b - 1) when a + b is not equal to 1. By substituting y_k = x_k + p, the recurrence can be transformed into a simpler form without the constant term. This transformation allows for the sequence x_k to be determined if y_k can be found. Understanding the role of p is crucial for solving the recurrence effectively.
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Consider the recurrence x_k+2 = ax_k+1 + bx_k + c where c may not be zero.

If a + b is not equal to 1 show that p can be found such that, if we set y_k = x_k + p, then y_k+2 = ay_k+1 + by_k. [Hence, the sequence x_k can be found provided y_k can be found]


First of all, sorry about the messiness, I don't know how to use LaTeX. Now, this is the question exactly as it is from the question sheet. My problem is, I don't understand the question. And its kind of really hard to start the question without understanding it :mad: . My biggest concern is, what the heck is p and where does it come from? The way I read it, p is just -c.

Thx in advance for any help.
 
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1.You should learn "tex".
2.Hypothetis:x_{k+2}=ax_{k+1}+bx_{k}+c (1)
y_{k}=x_{k}+p (2)
y_{k+2}=ay_{k+1}+by_{k} (3)
3.Question:p=...?

4.From (2) u have:
y_{k+2}=x_{k+2}+p (4)
Combining (1) and (4),u get:
y_{k+2}=ax_{k+1}+bx_{k}+c+p (5)
Equate (5) with (3),make use of (2) and extract 'p':

Answer:p=\frac{c}{a+b-1}

Daniel.
 
Ah, it all makes sense. Can't believe I never saw that. Thx alot!
 
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