Solving Log Algebra: Understanding Integrals with (2/2-z) + (2/1+2z)dz

[franky2727]

half way through a question and I'm stumped, I've got all the answers and I'm just revising so the answers no problem just don't get how the integral of {(2/2-z) + (2/1+2z)}dz become -2ln|2-z|+ln|1+2z| +c

 

[Dick]

Do the two terms separately. For 2/(2-z) use the u substitution u=2-z. What substitution would you use for the second term?