The integral of the expression {(2/2-z) + (2/1+2z)}dz can be solved using specific substitution techniques. For the first term, the substitution u = 2 - z simplifies the integration process, leading to the result -2ln|2-z|. The second term, 2/(1+2z), requires the substitution u = 1 + 2z, resulting in ln|1+2z|. The final solution combines these results with a constant of integration, yielding -2ln|2-z| + ln|1+2z| + c.
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