Solving Matrix Equations: x = Cx + d to x = [(I - C)^(-1)]d

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To solve the matrix equation x = Cx + d and transform it into x = [(I - C)^(-1)]d, one must first rewrite the equation as Ix = Cx + d, where I is the identity matrix. By rearranging the equation, it becomes (I - C)x = d. This allows for the application of the inverse of (I - C), leading to the solution x = [(I - C)^(-1)]d. Understanding this process requires familiarity with matrix operations, particularly inverses. Resources such as tutorial videos can aid in grasping these concepts.
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Homework Statement


How does one go from

x = Cx + d

to

x = [(I − C)^(-1)]d

in a matrix equation?


Homework Equations


x = Cx + d

x = [(I − C)^(-1)]d

The Attempt at a Solution


I tried to Google.
 
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Do you need to get there using a matrix equation or just know how to get there? I know how to get to that equation without matrices. I would not know how to get there with them though. Matrices were never my strong suit.

edit:
http://www.youtube.com/watch?v=tuepwWQ4_mM I think you might find this helpful.
 
Cinitiator said:

Homework Statement


How does one go from

x = Cx + d

to

x = [(I − C)^(-1)]d

in a matrix equation?


Homework Equations


x = Cx + d

x = [(I − C)^(-1)]d

The Attempt at a Solution


I tried to Google.

I is the identity matrix, yes? Ix=x. So write the equation as Ix=Cx+d. Can you take it from there?
 
Think about how you'd solve this with your usual numbers
x=ax+b
(1-a)x=b
x=(1-a)^-1 b
You followin'?
 
Shootertrex said:
Do you need to get there using a matrix equation or just know how to get there? I know how to get to that equation without matrices. I would not know how to get there with them though. Matrices were never my strong suit.
The equation uses matrices, so if you don't feel confident answering a question that involves matrices, you shouldn't respond.
Shootertrex said:
edit:
http://www.youtube.com/watch?v=tuepwWQ4_mM I think you might find this helpful.
 
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