Solving Momentum Problem: Superman & Metropolis Express Collision

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The discussion revolves around a physics problem involving Superman stopping a train to save Lois Lane. Participants are calculating Superman's velocity before the collision and the forces involved during the impact. Initial calculations yielded an incorrect velocity of 6000 m/s, which was later corrected to 60,000 m/s, raising questions about the feasibility of such a value. The average force exerted by Superman on the train was calculated to be 60,000,000 N, prompting further discussion about the implications of this force given Superman's mass. The conversation highlights the complexities of momentum and force calculations in this hypothetical scenario.
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Homework Statement



Lois Lane has been tied to the tracks and the Metropolis Express (m=200, 000 kg) is racing toward her at a velocity of +30 m/s. Superman (m=100kg) arrives just in time and comes hurtling at the train, collides with it, and stops it just before it runs over Lois. NOTE: Both Superman and the train come to a stop.

a)What was Man of Steel's velocity prior to his collision with the train?

b) It took 0.20 seconds for the train, and Superman, to come to a stop, what was the average force exerted by Superman on the train?

c) What was the average force exerted by the train on Superman?

Homework Equations





The Attempt at a Solution



i thought for part a:

200000(0)+100(v)=200000(30)+100(0)

v=6000 m/s?! it doesn't make sense..

part b)

J=Fave(t)
P=m(V)

100(v)=Fave(.2)

I realized i had to find Superman's velocity...
 
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Check your calculation, your answer is smaller than what it should be (by a factor of ten.)

But even with your smaller answer, why doesn't it make sense? A 200,000 kg train moving at 30 m/s has a lot of momentum.
 
cdotter said:
Check your calculation, your answer is smaller than what it should be (by a factor of ten.)

But even with your smaller answer, why doesn't it make sense? A 200,000 kg train moving at 30 m/s has a lot of momentum.

sorry, it was 60,000!
what does it mean for the average force exerted by the train on superman?!
 
also, i got 60, 000, 000 N for part b...
which doesn't seem right for superman who has a mass of 100 kg..
Favg(.2)=100(60,000)
 
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