Solving Navier Stokes & energy equations with different coordinates

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SUMMARY

The discussion focuses on solving the Navier-Stokes and energy equations for fluid analysis in a subsea pipe using different coordinate systems. The user initially derived the velocity equation in cylindrical coordinates but attempted to solve the energy equation in Cartesian coordinates. It was concluded that using cylindrical coordinates for both equations is preferable to maintain consistency and simplify the analysis. The relationship between the two coordinate systems was clarified, emphasizing that the energy equation should be adapted to cylindrical coordinates for accurate results.

PREREQUISITES
  • Understanding of Navier-Stokes equations
  • Familiarity with energy equations in fluid dynamics
  • Knowledge of cylindrical and Cartesian coordinate systems
  • Basic principles of partial differential equations (PDEs)
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  • Learn how to derive the energy equation in cylindrical coordinates
  • Study the application of Navier-Stokes equations in fluid dynamics
  • Explore the implications of using PDEs in thermal analysis
  • Investigate numerical methods for solving fluid dynamics equations
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Fluid dynamics engineers, researchers in thermal analysis, and students studying advanced fluid mechanics will benefit from this discussion.

shevir1
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Hi all I am conducting a fluid analysis on water flowing through a subsea pipe.

Having used navier stokes equation, i derived the equation for velocity in the r-direction (using cylindrical coordinates.

But when initially solving the energy equation to determine temperature distribution I have used the cartesian coordinates, x & y

From the picture I have attached am I correct in proceeding to solve the energy equation, if I were to just differentiate my velocity equation result and substitute back into the energy equation?
From my knowledge the Y direction in cartesian corresponds with the R direction in the cyclindrical hence my reasoning for proceeding this way.
 

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shevir1 said:
From my knowledge the Y direction in cartesian corresponds with the R direction in the cyclindrical hence my reasoning for proceeding this way.
These are the actual relationships between cylindrical and cartesian coordinates.
x = r \cos \theta
y = r \sin \theta
r^2 = x^2 + y^2
Why don't you just use the energy equation in cylindrical coordinates? That's the easiest way to proceed.
\frac{1}{r} \frac{d}{dr} \left( r \frac{dT}{dr} \right) = - \frac{\mu}{k} \left( \frac{dv_z}{dr} \right)^2
However, this model is only valid if the temperature is a function of radius only. If it also depends on z, your energy equation becomes a PDE.
 
yes this is what i assumed.
of course it is better to work in just one coordinate system.

thanks
 

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