Solving Non-Homogeneous Differential Equations with Two y' Terms

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Homework Statement



I have to find the differential of (y-xy')^2=x^2+y^2.Now,I have solved hom. equations but this is different because there are two y'. I know how to prove that it is a hom. equation of degree zero, so we can skip that, but how to solve this? Some hints would be highly appreciated.

Homework Equations





The Attempt at a Solution

 
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What happens if you take the square root of both sides of the equation?
 
(y-xy')=sqrt(x^2+y^2)
 
Do you know how to solve homogeneous equations of the form y'= f(x,y)?

Can you write (y-xy')=sqrt(x^2+y^2) as y'=f(x,y)?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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