Solving Norton Equivalent Circuits - Help Needed

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Discussion Overview

The discussion revolves around solving Norton equivalent circuits, specifically focusing on understanding the configuration of resistors in a circuit with a closed switch. Participants are addressing a homework problem that involves identifying series and parallel relationships among resistors and determining the Norton resistance.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant expresses difficulty in reducing the circuit to a manageable format and is unsure about the configuration of resistors when the switch is closed.
  • Another participant points out that closing the switch shorts the 135 ohm resistor, suggesting it is no longer part of the circuit.
  • A later reply emphasizes the importance of understanding the effect of the switch on the circuit and suggests that the network may become easier to solve once this is clarified.
  • Participants discuss the approach of suppressing sources to find the Norton or Thevenin resistance from the load terminals.
  • One participant mentions the potential benefit of solving the circuit in stages, converting between Norton and Thevenin equivalents as needed.

Areas of Agreement / Disagreement

Participants generally agree on the effect of the closed switch on the 135 ohm resistor, but there is no consensus on the overall approach to solving the circuit or the specific steps to take next.

Contextual Notes

Participants acknowledge the need for clarity on the configuration of resistors and the impact of the switch, but there are unresolved aspects regarding the order of operations and the overall circuit analysis.

Who May Find This Useful

This discussion may be useful for students working on circuit analysis, particularly those learning about Norton and Thevenin equivalents and the impact of circuit components like switches on resistor configurations.

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Homework Statement



Having some Difficulty in starting the second question on this sheet. i have managed to find examples and worked my way through the first question, but unfortunately my tutor has decided to move onto pastures new, and we have an assignment to complete but no tutor which has left me in a slight pickle!

The main problem at the moment is reducing the circuit into a format where i can understand and work with it.
im assuming the switch is redundant as it states it is closed, but from there onwards, I am not sure which are in parallel and which are in series (as I am mechanically biased = clueless)

Homework Equations



i have all the equations necessary and i have worked out equivalent resistances etc before, but it is literally just knowing the order of things to do with this and what each are doing.

The Attempt at a Solution



My first attempt was to close the switch, assume that the 180 and 270 ohm resistors are in series, giving me 450ohm in parallel with the 90. and then having the equivalent (75) in series with the 135. giving me a 200ohm resistor, 6A and the load.

any help would be much appreciated as I am a bit aimless at the minute without a tutor to point me in the right direction.

thanks very much.
 

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If the switch is closed, the 135 ohm resistor is shorted and no longer in the circuit.
 
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Manners said:

Homework Statement



Having some Difficulty in starting the second question on this sheet. i have managed to find examples and worked my way through the first question, but unfortunately my tutor has decided to move onto pastures new, and we have an assignment to complete but no tutor which has left me in a slight pickle!

The main problem at the moment is reducing the circuit into a format where i can understand and work with it.
im assuming the switch is redundant as it states it is closed, but from there onwards, I am not sure which are in parallel and which are in series (as I am mechanically biased = clueless)

Homework Equations



i have all the equations necessary and i have worked out equivalent resistances etc before, but it is literally just knowing the order of things to do with this and what each are doing.

The Attempt at a Solution



My first attempt was to close the switch, assume that the 180 and 270 ohm resistors are in series, giving me 450ohm in parallel with the 90. and then having the equivalent (75) in series with the 135. giving me a 200ohm resistor, 6A and the load.

any help would be much appreciated as I am a bit aimless at the minute without a tutor to point me in the right direction.

thanks very much.

First determine what closing the the switch S1 accomplishes. For example, how is the 135 Ω resistor affected? Once you've sorted that out the network should look easier to solve for the Norton resistance.

When determining the Norton or Thevenin resistance you want to suppress the sources and then find the resistance of the resulting network as "seen" from the perspective of the load terminals (load removed, of course).

One suggestion: sometimes it is convenient to solve circuits in stages, converting Norton to Thevenin and back along the way, gobbling up components as you proceed across the circuit. Once you've figured out S1's effect you might find this hint helpful... :wink:
 
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Ah, so the switch shorts out the 135 resistor, and because its an open circuit due to removing the current source I am just dealing with the top three resistors and the load.
Right ill have a bash at that tonight and see if i can find an old example somewhere to walk through with it. thank you both for the advice.
 

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